python 서로 겹치지 않는 세자리 수 배열 만들기

numbers = [ str(x) for x in range(1, 10) ] 
#참조할 배열을 만들고

candidates = [ 
    numbers[x] + numbers[y] + numbers[z] 
    for x in range(9) 
    for y in range(9) 
    for z in range(9) 
    if x != y and y != z and z != x 
]
#앞서 작성한 참조배열을 가지고 만들면 됨

>>> can
['123', '124', '125', '126', '127', '128', '129', '132',
'134', '135', '136', '137', '138', '139', '142', '143', 
'145', '146', '147', '148', '149', '152', '153', '154', 
'156', '157', '158', '159', '162', '163', '164', '165', 
'167', '168', '169', '172', '173', '174', '175', '176', 
'178', '179', '182', '183', '184', '185', '186', '187', 
'189', '192', '193', '194', '195', '196', '197', '198', 
'213', '214', '215', '216', '217', '218', '219', '231', 
'234', '235', '236', '237', '238', '239', '241', '243', 
'245', '246', '247', '248', '249', '251', '253', '254', 
... 생략
'954', '956', '957', '958', '961', '962', '963', '964', 
'973', '974', '975', '976', '978', '981', '982', '983', 
'984', '985', '986', '987']

 

 

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